4+(8/x-3)=(-9/(x-3)^2)

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Solution for 4+(8/x-3)=(-9/(x-3)^2) equation:



4+(8/x-3)=(-9/(x-3)^2)
We move all terms to the left:
4+(8/x-3)-((-9/(x-3)^2))=0
Domain of the equation: x-3)!=0
x∈R
Domain of the equation: (x-3)^2))!=0
x∈R
We get rid of parentheses
8/x-((-9/(x-3)^2))-3+4=0
We calculate fractions
8x/(-2x^2)+(-((-9*x)/(-2x^2)-3+4=0
We add all the numbers together, and all the variables
8x/(-2x^2)+(-((-9x)/(-2x^2)-3+4=0
We calculate fractions
We do not support expression: x^3

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